Step-by-step explanation:
Let
base=x
height=x+5
we know that in a parrelogram
[tex]\boxed{\sf Area=base×height}[/tex]
[tex]{:}\rightarrowtail\sf x(x+5)=204 [/tex]
[tex]{:}\rightarrowtail\sf x^2+5=204 [/tex]
[tex]{:}\rightarrowtail\sf x^2=204-5 [/tex]
[tex]{:}\rightarrowtail\sf x^2=199 [/tex]
[tex]{:}\rightarrowtail\sf x=\sqrt {199}[/tex]
[tex]{:}\rightarrowtail\sf x=14.1[/tex]
[tex]{:}\rightarrowtail\sf base=14.
1feet[/tex]
[tex]{:}\rightarrowtail\sf Height =14.1+5=19.1feet [/tex]