in Figure 5.26 to the right, ABCD
is asquare. Find the measure of
<ABD
![in Figure 526 to the right ABCDis asquare Find the measure ofltABD class=](https://us-static.z-dn.net/files/d62/83d651420845a2c2c2eb3f524dc44647.jpg)
Answer:
∠ABD = 45°
Step-by-step explanation:
Since ABCD is a square, its diagonals (Line BD) bisect the angles of the corners of the square (∠ABC) into two equal angles (∠ABD and ∠CBD). The angle of each corner is 90° so you can find ∠ABD.
2(∠ABD) = 90°
∠ABD = 90° ÷ 2
∠ABD = 45°