If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(You will need to balance
the equation first.)
Na + Cl2 -> NaCl A. They are equal B. Na C. Cl2 D. NaCl

Once balanced you get 2Na + Cl₂ ⇒ 2NaCl. Sodium is the limiting reagent because it would produce the smallest amount of the product (NaCl)–while chlorine is the excess reagent. Based off of the Na in the balanced equation, it would produce 3 moles of NaCl, and for Cl₂ it would produce an excess of 6 moles of NaCl. [It'd be wise to utilize stoichiometric factors to get a good grasp of this]

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If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(You will need to balance the equation first.) Na + Cl2 -> NaCl A. They are equal B. Na C. Cl2 D. NaCl

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If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(You will need to balance
the equation first.)
Na + Cl2 -> NaCl A. They are equal B. Na C. Cl2 D. NaCl