Given:
A line passes through two points are (2,11) and (-8,-19).
To find:
The equation of the line.
Solution:
The line passes through two points are (2,11) and (-8,-19). So, the equation of line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-11=\dfrac{-19-11}{-8-2}(x-2)[/tex]
[tex]y-11=\dfrac{-30}{-10}(x-2)[/tex]
[tex]y-11=3(x-2)[/tex]
Using distributive property, we get
[tex]y-11=3(x)+3(-2)[/tex]
[tex]y-11=3x-6[/tex]
Adding 11 on both sides, we get
[tex]y=3x-6+11[/tex]
[tex]y=3x+5[/tex]
Therefore, the equation of line is [tex]y=3x+5[/tex]. So, the missing values are 3 and 5 respectively.