Question

to determine the height of a steep cliff an experimenter stations a sensor on the top of the cliff then fires a pellet vertically upward with an initial velocity of 80 m/s . the sensor reports that the pellet reached a maximum height 3 meters above the edge of the cliff. how high is the cliff?​
a. 77 m
b. 237 m
c. 317 m
d. 637 m
e. 797 m​

Answer 1

Answer:

c. 317 m

Explanation:

Vertical Launch Upwards

It occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=\frac{v_o^2}{2g}$

We'll assume the acceleration of gravity as $g=10\ m/s^2$.The pellet is vertically upward launched with vo=80 m/s. The maximum height is:

$\displaystyle h_m=\frac{80^2}{2*10}=320$

$h_m = 320\ m$

That height is 3 meters above the edge of the cliff, thus the cliff is 320-3=317 m hight

c. 317 m