Question

What mass of water would increase in temperature from 45.0℃ to 98.0℃ after absorbing 6830 J of energy?

Answer 1

Mass of water : 30.83 g

Further explanation  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

• ∆T = temperature difference

$\tt \Delta T=T_f(final)-T_i(initial)\\\\\Delta T=98-45=53^oC$

• mass of water

$\tt m=\dfrac{Q}{c\times \Delta T }\\\\m=\dfrac{6830}{4.18\times 53}\\\\m=30.83~g$