The moles of the reactant and the product produced in the reaction is given by the stoichiometric law. The moles of water produced in the reaction is 2.79 mol.
What is stoichiometric law?
The stoichiometric law states the moles of the reactant and the product in the reaction are equivalent to the stoichiometric coefficient.
For the equation given, stoichiometric law states that:
[tex]\rm 7\;mol\;O_2=6\;mol\;H_2O[/tex]
The moles of water produced from the 3.25 moles of oxygen are:
[tex]\rm 7\;mol\;O_2=6\;mol\;H_2O\\\\3.25\;mol\;O_2=\dfrac{6}{7} \;\times\;3.25\;mol\;H_2O\\\\3.25\;mol\;O_2=2.79\;mol\;H_2O[/tex]
The moles of water produced in the reaction are 2.79 mol. Thus, option D is correct.
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