The molecular formula of a compound that has a molar mass of 180 g/mol and its empirical formula is CH2O is
C6H12O6
calculation
step 1: Given the empirical formula divide the gram molecular mass with
empirical formula mass
that is empirical formula mass (cH2O) = 12+2+16 = 30 g/mol
gram molecular mass = 180 g/mol
= 180 g/mol/30 g/mol = 6
step 2: multiply each subscripts in the empirical formula by 6
that is [CH2O]6
molecular formula is therefore= C6H12O6
