Respuesta :
b) Ca2+ + Co32- -> CaCo3
Combination reaction
d) 2CCl4 + CrO42- -> 2CoCl2+ CrO2Cl2+2Cl-
REDOX reaction
e) Ca+ F2-> CaF2
Combination reaction
f) 2Li+H2-> 2LiH
Combination reaction
g) Ba(NO3)2+Na2SO4-> 2NaNo3+BaSO4
Double replacement reaction
h) CuO+H2-> Cu+H20
Decomposition Reaction
I) Zn+2HCl-> ZnCl2+H2
J) 2FeCl2+Cl2-> 2FeCl3
Combination reaction
d) 2CCl4 + CrO42- -> 2CoCl2+ CrO2Cl2+2Cl-
REDOX reaction
e) Ca+ F2-> CaF2
Combination reaction
f) 2Li+H2-> 2LiH
Combination reaction
g) Ba(NO3)2+Na2SO4-> 2NaNo3+BaSO4
Double replacement reaction
h) CuO+H2-> Cu+H20
Decomposition Reaction
I) Zn+2HCl-> ZnCl2+H2
J) 2FeCl2+Cl2-> 2FeCl3
Explanation :
(b) [tex]Ca^{2+}+CO_3^{2-}\rightarrow CaCO_3[/tex]
This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.
(d) [tex]2CCl_4+CrO_4^{2-}\rightarrow 2COCl_2+CrO_2Cl_2+2Cl^-[/tex]
This reaction is a redox reaction or oxidation-reduction reaction in which sulfur get oxidized and oxygen get reduced.
(e) [tex]Ca+F_2\rightarrow CaF_2[/tex]
This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.
(f) [tex]2Li+H_2\rightarrow 2LiH[/tex]
This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.
(g) [tex]Ba(NO_3)_2+Na_2SO_4\rightarrow 2NaNO_3+BaSO_4[/tex]
This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.
(h) [tex]CuO+H_2\rightarrow Cu+H_2O[/tex]
This reaction is a single displacement reaction in which the most reactive metal displaces the least reactive metal and forms different product.
(I) [tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]
This reaction is a single displacement reaction in which the most reactive metal displaces the least reactive metal and forms different product.
(J) [tex]2FeCl_2+Cl_2\rightarrow 2FeCl_3[/tex]
This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.