Respuesta :
Given:
initial value = 16,000
depreciation rate = 35%
current value = 2,000
equation:
2,000 = 16,000 (1-r)^t
2,000 = 16,000 (1-0.35)^t
2,000 = 16,000 (0.65)^t
2,000/16,000 = 0.65^t
0.125 = 0.65^t
log(0.125) = log(0.65^t)
log(0.125) = log(0.65) * t
log(0.125) / log(0.65) = t
4.82 = t
or 5 years
16,000 * 0.65 = 10,400
10,500 * 0.65 = 6,760
6,760 * 0.65 = 4,394
4,394 * 0.65 = 2,856.10
2,856.1 * 0.65 = 1,856.47
initial value = 16,000
depreciation rate = 35%
current value = 2,000
equation:
2,000 = 16,000 (1-r)^t
2,000 = 16,000 (1-0.35)^t
2,000 = 16,000 (0.65)^t
2,000/16,000 = 0.65^t
0.125 = 0.65^t
log(0.125) = log(0.65^t)
log(0.125) = log(0.65) * t
log(0.125) / log(0.65) = t
4.82 = t
or 5 years
16,000 * 0.65 = 10,400
10,500 * 0.65 = 6,760
6,760 * 0.65 = 4,394
4,394 * 0.65 = 2,856.10
2,856.1 * 0.65 = 1,856.47
Based on the calculations, the age of Devon's car is approximately equal to 5 years.
Given the following data:
Initial value = $16,000
Rate of depreciation = 35% = 0.35
Current value = $2,000
How to calculate the age of Devon's car?
Mathematically, the equation which can be used to determine the age of Devon's car is given by:
2,000 = 16,000(1 - r)^t
Where:
- t is the age of the car in years.
- r is the rate of depreciation.
Substituting the given parameters into the equation, we have:
2,000 = 16,000(1 - 0.35)^t
2,000 = 16,000(0.65)^t
2,000/16,000 = 0.65^t
0.125 = 0.65^t
Taking the log of both sides, we have:
log(0.125) = log(0.65^t)
log(0.125) = log(0.65) × t
t = log(0.125)/log(0.65)
t = 0.125/0.65
Age, t = 4.82 ≈ 5 years.
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