Question

HELP!!!!This question is typical on some driver's
license exams: A car moving at 49 km/h skids
12 m with locked brakes.
How far will the car skid with locked brakes
at 122.5 km/h? Assume that energy loss is
due only to sliding friction.
Answer in units of m.

Answer 1

Answer:

d=75 m

Explanation:

Before Skidding

$v^2-v_o^2=2ad$

$0^2-49^2=2a(12)$

After Skidding

$v^2-v_o^2=2ad$

$0^2-122.5^2=2ad$

$\frac{49^2}{122.5^2}=\frac{12}{d}$

$d=75 m$

Hope it helps