What is the factorization of the trinomial below?
x^2- 5x+4
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The factors of the quadratic equation x²- 5x + 4 are (x - 4)(x - 1) option (A) is correct.
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We have a quadratic equation:
= x²- 5x + 4
= x² -x - 4x + 4
= x(x - 1) - 4(x - 1)
= (x - 4)(x - 1)
Thus, the factors of the quadratic equation x²- 5x + 4 are (x - 4)(x - 1) option (A) is correct.
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