Question

A school paid $248 for new basketballs and soccer balls. The number of basketballs purchased was 6 less than 3 times the number of soccer balls purchased. Basketballs cost $28 each and soccer balls cost $20 each. How many soccer balls did the school purchase?​

Answer 1

Answer:

The school purchased 4 soccer balls.

Step-by-step explanation:

Total cost of basketball and soccer ball = $248

We are given: The number of basketballs purchased was 6 less than 3 times the number of soccer balls purchased.

We can write it as

x = Soccer Balls

3x-6 = Basketballs

Cost of each Soccer Ball = $20

Cost of each Basketball = $28

The equation will become

$20(x)+28(3x-6)=248$

Solving the equation to find x

$20(x)+28(3x-6)=248\\20x+84x-168=248\\104x=248+168\\104x=416\\x=\frac{416}{104} \\x=4$

So, Soccer balls x = 4

Basketballs = 3x-6 = 3(4)-6 = 12-6 = 6

So, the school purchased 4 soccer balls.