Question

What mathematical formula do you use for the following question. A rectangle whose perimeter is 104 feet has a length that is 12 feet longer than its width what is the area of the rectangle. The answer is 640 square feet 20 feet wide by 32 feet long.

Answer 1

Answer:

Width = 20 inches and Length = 32 inches

Area of rectangle = 640 feet²

Step-by-step explanation:

Perimeter of rectangle = 104 feet

Let width of rectangle = x

Length of rectangle = x+12

We need to find area of rectangle.

First we need to find value of x

The formula used to calculate perimeter of rectangle is: $Perimeter= 2(Length+Width)$

Putting values and finding x

$Perimeter= 2(Length+Width)\\104 = 2(x+12+x)\\104=2(2x+12)\\104=4x+24\\4x=104-24\\4x=80\\x=\frac{80}{4}\\x=20$

So, Value of x= 20

So, Width x= 20 inches

Length = x+12 = 20+12 = 32 inches

So, Width = 20 inches and Length = 32 inches

Now finding Area

The formula used is: $Area=Length\times Width$

Putting values and finding area

$Area=Length\times Width\\Area=20\times 32\\Area=640 \ feet^2$

Area of rectangle = 640 feet²