PLEASE HELP ASAP.
A triangle with a vertex at point Y(-3, 7) is dilated by a scale factor represented by the coordinate pair (2/3x, 2/3y ). What is the location of Y'?

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PLEASE HELP ASAP A triangle with a vertex at point Y3 7 is dilated by a scale factor represented by the coordinate pair 23x 23y What is the location of Y Please class=

Respuesta :

Answer:

[tex]Y' = (-2, 4\frac{2}{3})[/tex]

Step-by-step explanation:

Given

[tex]Y = (-3,7)[/tex]

[tex]Scale\ Factor = (\frac{2}{3}x,\frac{2}{3}y)[/tex]

Required

Determine Y'

Y' can be solved by multiplying the scale factor by Y

i.e.

[tex]Y' = Scale\ Factor * Y[/tex]

For, the x coordinates.

[tex]Y' = \frac{2}{3}x[/tex]

Where

[tex]x = -3[/tex]

[tex]Y' = \frac{2}{3} * -3[/tex]

[tex]Y' = \frac{-6}{3}[/tex]

[tex]Y = -2[/tex]

For the y coordinates:

[tex]Y' = \frac{2}{3}y[/tex]

Where

[tex]y = 7[/tex]

[tex]Y' = \frac{2}{3} * 7[/tex]

[tex]Y' = \frac{14}{3}[/tex]

[tex]Y' = 4\frac{2}{3}[/tex]

Hence:

[tex]Y' = (-2, 4\frac{2}{3})[/tex]

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