Question

\The graph for the equation y = negative x + 2 is shown below. On a coordinate plane, a line with positive slope goes through (0, 2) and (2, 0). If another equation is graphed so that the system has an infinite number of solutions, which equation could that be? y = negative 2 (x minus 1) y = negative (x + 2) y = negative one-fourth (4 x minus 8) y = negative one-half (x + 4)

Answer 1

An infinite number of solutions is generated with a multiple of the first function, hence, the correct option is:

$y = -\frac{1}{4}(4x - 8)$

The graph given is:

$y = -x + 2$

When two equations are multiple, the system involving these two equations has infinite solutions.

Among the options, the multiple of the original function is:

$y = -\frac{1}{4}(4x - 8)$

$y = -x + 2$

Hence, $y = -\frac{1}{4}(4x - 8)$ is the correct option.

A similar problem is given at https://brainly.com/question/25718527

Answer 2

Answer:

d

Step-by-step explanation: