Question

HELP
How many moles of Ag (silver) contain 4.49 x 1023 atoms Ag?
27.0 mol
0.746E23 mol
0.746 mol
0.746E24 mol

Answer 1

C, 0.746 mol Ag.

1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag

Answer 2

The moles of Ag that contain 4.49  $\rm \times\;10^2^3$ atoms have been 0.745 moles.

The number of atoms in a mole can be given by the Avagadro number. The Avagadro number has been equal to the number of atoms in a mole of compounds. The Avagadro number has been constant with a value of 6.023 $\rm \times\;10^2^3$.  

6.023 $\rm \times\;10^2^3$ atoms = 1 mole

So, for the given 4.49  $\rm \times\;10^2^3$ atoms:

4.49  $\rm \times\;10^2^3$ atoms = $\rm \dfrac{1}{6.023\;\times\;10^2^3}\;\times\;4.49\;\times\;10^2^3$ moles

4.49  $\rm \times\;10^2^3$ atoms = 0.745 moles.

The moles of Ag that contain 4.49  $\rm \times\;10^2^3$ atoms have been 0.745 moles.

For more information about the moles of an atom, refer to the link:

https://brainly.com/question/4783755