Prove that Triangle abc and Triangle edc are similar

The corresponding sides have equal ratios, so the triangles are similar triangles.
From the question, we have:
In triangle ABC, AB = 3, BC = 5 and AC = 4
In triangle EDC, ED = 9, DC = 15 and EC = 12
For the triangles to be similar, then the corresponding sides must have an equivalent ratio.
This is calculated as:
[tex]\mathbf{Ratio = \frac{ED}{AB} = \frac{DC}{BC} = \frac{EC}{AC}}[/tex]
So, we have:
[tex]\mathbf{Ratio = \frac{9}{3} = \frac{15}{5} = \frac{12}{4}}[/tex]
[tex]\mathbf{Ratio =3 = 3 = 3}[/tex]
[tex]\mathbf{Ratio =3}[/tex]
Because the corresponding sides have equal ratios, then the triangles are similar.
Read more about similar triangles at:
https://brainly.com/question/19738610