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Answer:
We conclude that the slope of the line that is perpendicular to [tex]y=3x+6[/tex] will be: -1/3
Step-by-step explanation:
Given the equation
[tex]y=3x+6[/tex]
Comparing with the slope-intercept form
[tex]y=mx+b[/tex]
Here, m is the slope and b is the y-intercept.
so
[tex]y=3x+6[/tex]
Here the slope of line = m = 3
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
the slope of the perpendicular line will be: -1/3
Therefore, we conclude that the slope of the line that is perpendicular to [tex]y=3x+6[/tex] will be: -1/3