Question

Whats the distance (7,0) and (-8,45)

Answer 1

Answer:

$d = 15\sqrt{10}$

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS

Algebra II

• Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (7, 0)

Point (-8, 45)

Step 2: Find distance d

1. Substitute:                    $d = \sqrt{(-8-7)^2+(45-0)^2}$
2. Subtract:                       $d = \sqrt{(-15)^2+(45)^2}$
3. Exponents:                   $d = \sqrt{225+2025}$
4. Add:                              $d = \sqrt{2250}$
5. Simplify:                        $d = 15\sqrt{10}$