Answer:
For this case, we have the following equation (according to the comments):
First, we factor the quadratic expression in the denominator:
Then, we multiply both sides of the equation by (a-2) (a + 2):
Later, canceling similar terms we have:
We do distributive property on the left side of the equation:
By grouping variables and constant terms we have:
Rewriting we have:
Finally, by clearing "a" we have:
Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.
Answer:
the student correct, but the value of a= -2 is an extraneous solution
Answer:
No, the student did not check the solution to the derived equation in the original equation.
No, a possible solution is a = –2, but it does not check in the original equation because it makes two of the denominators equal to zero.
No, a = –2 is an extraneous solution, and there is no solution to the original rational equation.
Step-by-step explanation:
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