Question

How much heat is needed to raise the temperature of an empty 2.0 x 101 kg vat made of

iron from 10.0ºC to 90.0ºC?​

Answer 1

Answer:

Q = 7272 Kilojoules.

Explanation:

Given the following data;

Mass = 2.0*101kg = 202kg

Initial temperature, T1 = 10°C

Final temperature, T2 = 90°C

We know that the specific heat capacity of iron = 450J/kg°C

*To find the quantity of heat*

Heat capacity is given by the formula;

$Q = mcdt$

Where;

• Q represents the heat capacity or quantity of heat.

• m represents the mass of an object.

• c represents the specific heat capacity of water.

• dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 10

dt = 80°C

Substituting the values into the equation, we have;

$Q = 202*450*80$

Q = 7272KJ or 7272000 Joules.