Question

Mrs. Mireles needs to hire landscapers to maintain her yard. Company L charges $250 per month plus $30 per hour. Company S charges $200 per month plus $35 per hour. Which inequality can be used to find x, the minimum number of hours each company would have to work so that the total charges from Company L is less than the total charges from Company S?

Answer 1

Answer:

10 hours

Step-by-step explanation:

Step one:

given information

Company L charges

monthly charge= $250

hourly charge= $30

let the total charge be y

and the number of hours be x

y=30x+250----------1

Company S charges

monthly charge= $200

hourly charge= $35

let the total charge be y

and the number of hours be x

y=35x+200------------2

Step two:

equating 1 and 2

30x+250=35x+200

collect like terms

30x-35x=200-250

-5x=-50

x=50/5

x=10

10 hours