Answer:
We will use substitution to solve this system for x.
[tex]x - 2y = 27\\y = 5x\\\\x - 2(5x) = 27\\\\x - 10x = 27\\\\-9x = 27\\\\x = -3[/tex]
Now that we know what x is, we can determine y by pluging in -3 for x in one of the original equations. I will use the first one.
[tex]-3 - 2y = 27\\\\-2y = 30\\\\y = -15\\[/tex]
We now have our solution.
D. [tex](-3, -15)[/tex]
We can check our answer by pluging the solution into one of the original equations to see if both sides equal each other. I will use the first equation.
[tex]-3 - 2(-15) = 27\\\\-3 + 30 = 27\\\\27 = 27[/tex]
Since the equation checks out, our solution is correct.
