Question

A child kicks a ball with an initial velocity of 8.5 meters per second at an angle of 35.00 degrees above the horizontal. The ball has an initial vertical velocity of 4.9 meters per second and a total time of flight of 1.0 second. The horizontal component of the ball's initial velocity is approximately

Answer 1

Answer:

6.96 m/s

Explanation:

Horizontal component = V cos α

V= initial velocity of the ball= 8.5 m/s

α = 35°

Horizontal component = 8.5 cos35 = 6.96 m/s

Therefore, the horizontal component of the balls initial velocity is 6.96 m/s

Answer 2

This question involves the concepts of projectile motion, Pythagora's theorem, and the horizontal and vertical components of velocity.

The horizontal component of the ball's initial velocity is "6.94 m/s".

This is an example of a projectile motion with both the horizontal and vertical components of the velocity. The resultant velocity, in this case, can be found using Pythagora's theorem.

$v^2=v_x^2+v_y2$

where,

v = resultant speed = 8.5 m/s

vx = horizontal component of speed = ?

vy = vertical component of speed = 4.9 m/s

Therefore,

$(8.5\ m/s)^2=v_x^2+(4.9\ m/s)^2\\\\v_x=\sqrt{(8.5\ m/s)^2-(4.9\ m/s)^2}\\\\v_x=6.94\ m/s$

Learn more about Pythagora's Theorem here:

https://brainly.com/question/343682?referrer=searchResults

The attached picture shows the Pythagora's theorem.