Question

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume (in L) of the balloon if 0.80 moles of gas are added?

Answer 1

We know, when temperature and pressure is constant :

$\dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}$      ....1)

$n_1 = 3\ moles,\ V_1 = 1.50\ L$

$n_2 = 3 + 0.80 = 3.80 \ moles$

Let, final volume is $V_2$.

Putting all values in equation 1), we get :

$\dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}\\\\\dfrac{1.50}{3}=\dfrac{V_2}{3.80}\\\\V_2 = \dfrac{1.50\times 3.80}{3}\\\\V_2 = 1.9\ L$

Therefore, volume (in L) of the balloon if 0.80 moles of gas are added is 1.9 L.

Hence, this is the required solution.