Question

Your mather bougth 20 kilos of mangoes and atis combined. Mango is P 60.00per kilos and atis is P 40.00 per kilos.If she paod P 1000.00 for 20 kilos, how many kilos of each kind mather bought A.)Ifx is number of kilos mango and number of kilos of atis then the eguation is ? B.) Eguation for the cost of fruits. C.) The system of eguations are ? D.) Solve by any method. E.) Check if your result will satisfy the problem.

Answer 1

Answer:

A) $x+y=20$

B) Cost function is: $3x+2y = 50$

C) $x+y=20$, $3x+2y = 50$

D) $x=10, y=10$

E) Yes, the result satisfies the equations.

Step-by-step explanation:

Let number of kilos of mango bought = $x$

Let number of kilos of atis bought = $y$

Total number of kilos bought = 20

A) $x+y=20$

Cost of mango per kg = 60

Cost of mango for $x$ kg = $60x$

Cost of atis per kg = 40

Cost of mango for $y$ kg = $40y$

Total cost is: Cost of mango + Cost of atis = 1000

B) Cost function is:

$60x+40y=1000\\\Rightarrow 3x+2y = 50 ...... (2)$

C) System of equations are:

$x+y=20$ ...... (1)

$3x+2y = 50$...... (2)

D) Using elimination method:

Multiplying equation (1) with 2 and subtracting from (2):

$x = 10$

By equation (1):

$\Rightarrow y =10$

E) Putting both the values in LHS of equation (1):

10+10  = 20 = RHS

Putting both the values in LHS of equation (2):

$3\times 10 +2\times 10$ = 50 = RHS

Yes, the result satisfies the equations.

Answer 2

Answer:

What is it?

Step-by-step explanation: