Answer:
3. 147 [tex]ft^{3}[/tex] 4. [tex]\frac{160}{3} \pi[/tex] [tex]ft^{3}[/tex]
Step-by-step explanation:
3. Volume of a square pyramid = [tex](base.edge.length)^{2}[/tex] × [tex]\frac{height}{3}[/tex]
Variables:
V = volume
x = base edge length
h = height
V = [tex]x^{2}[/tex] × [tex]\frac{h}{3}[/tex]
x = 7 ft
h = 9 ft
Plug the values in the equation:
V = [tex]7^{2}[/tex] × [tex]\frac{9}{3}[/tex]
V = 49 × 3
V = 147 [tex]ft^{3}[/tex]
4. Volume of cone = [tex]\pi r^{2} \frac{h}{3}[/tex]
Variables:
V = volume
r = radius
h = height
V = [tex]\pi r^{2} \frac{h}{3}[/tex]
r = 8ft /2 = 4 ft (radius is half of the diameter)
h = 10 ft
V = [tex]\pi 4^{2} \frac{10}{3}[/tex]
V = [tex]\pi[/tex] × 16 × [tex]\frac{10}{3}[/tex]
V = [tex]\frac{160}{3} \pi[/tex] [tex]ft^{3}[/tex]
