Answer:
[tex]\frac{1}{6}[/tex]x-19
Step-by-step explanation:
[tex]\frac{2}{3}[/tex]x-9-[tex]\frac{1}{2}[/tex]x-10 = [tex]\frac{2}{3}[/tex]x-[tex]\frac{1}{2}[/tex]x-19
If you minus 9 and then minus 10, you are deducting 19 from the equation in total
[tex]\frac{2}{3}[/tex]x-[tex]\frac{1}{2}[/tex]x-19 = [tex]\frac{4}{6}[/tex]x-[tex]\frac{3}{6}[/tex]x-19
You would want to make the denominator of the fractions the same by multiplying the first fraction by 2, and the second fraction by 3 so that both denominators are 6.
[tex]\frac{4}{6}[/tex]x-[tex]\frac{3}{6}[/tex]x-19 = [tex]\frac{1}{6}[/tex]x-19
Now that their denominators are the same, you can directly do the working for the numerators (4-3=1) and keep the denominator the same. Tada!