Solve and state any extraneous solutions

[tex] \frac{3x}{x - 1} + 2 = \frac{3}{x - 1} [/tex]
[tex] \frac{3x}{x - 1} + \frac{2(x - 1) }{ x - 1} = \frac{3}{x - 1} [/tex]
[tex] \frac{3x}{x - 1} + \frac{2x - 2}{ x - 1} = \frac{3}{x - 1} [/tex]
[tex] \frac{3x + 2x - 2}{ x - 1} = \frac{3}{x - 1} [/tex]
[tex]3x + 2x - 2 = 3[/tex]
[tex]5x - 2 = 3[/tex]
[tex]5x = 3 + 2[/tex]
[tex]5x = 5[/tex]
[tex]x = \frac{5}{5} [/tex]
[tex]x = 1[/tex]