Answer:
The function [tex]f(x)= x^3-\mathbf{2}x^2-\mathbf{8}x[/tex]
Step-by-step explanation:
The zeros of the polynomial are: -2,4,0
We can write them as
x=-2, x=4, x=0
or
x+2=0,x-4=0,x=0
Multiplying all terms:
[tex](x+2)(x-4)(x)\\=((x-4)+2(x-4))(x)\\=x^2-4x+2x-8)x\\=(x^2-2x-8)x\\=x^3-2x^2-8x[/tex]
So, the function [tex]f(x)= x^3-\mathbf{2}x^2-\mathbf{8}x[/tex]
