Given:
The vertices are d(-10,0), e(-10,2), f(-5,2) and g(-5,0).
To find:
The coordinates of the vertices after reflection over the line x=-2.
Solution:
If figure reflected over the line x=a, then
[tex](x,y)\to (2a-x,y)[/tex]
Here, the figure is reflected over the line x=-2, then
[tex](x,y)\to (2(-2)-x,y)[/tex]
[tex](x,y)\to (-4-x,y)[/tex] ...(i)
Now,
For point d,
[tex](-10,0)\to (-4-(-10),0)[/tex]
[tex](-10,0)\to (-4+10,0)[/tex]
[tex](-10,0)\to (6,0)[/tex]
Similarly,
For point e,
[tex](-10,2)\to (-4-(-10),2)=(6,2)[/tex]
For point f,
[tex](-5,2)\to (-4-(-5),2)=(1,2)[/tex]
For point g,
[tex](-5,0)\to (-4-(-5),0)=(1,0)[/tex]
Therefore, the coordinates of vertices after a reflection over the line x=-2 are d prime (6,0), e prime (6,2), f prime, (1,2) and g prime (1,0).