Answer:
[tex]T_{2} = 200[/tex]
Step-by-step explanation:
Given
Geometry Progression
[tex]T_1 = 500[/tex]
[tex]T_4 = 32[/tex]
Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP
[tex]T_n = ar^{n-1}[/tex]
For first term: Tn = 500 and n = 1
[tex]500 = ar^{1-1}[/tex]
[tex]500 = ar^{0}[/tex]
[tex]500 = a[/tex]
[tex]a = 500[/tex]
For fought term: Tn = 32 and n = 4
[tex]32 = ar^{4-1}[/tex]
[tex]32 = ar^3[/tex]
Substitute 500 for a
[tex]32 = 500 * r^3[/tex]
Make r^3 the subject
[tex]r^3 = \frac{32}{500}[/tex]
[tex]r^3 = 0.064[/tex]
Take cube roots
[tex]\sqrt[3]{r^3} = \sqrt[3]{0.064}[/tex]
[tex]r = \sqrt[3]{0.064}[/tex]
[tex]r = 0.4[/tex]
Using: [tex]T_n = ar^{n-1}[/tex]
[tex]n = 2[/tex] [tex]r = 0.4[/tex] and [tex]a = 500[/tex]
[tex]T_{2} = 500 * 0.4^{2-1}[/tex]
[tex]T_{2} = 500 * 0.4^1[/tex]
[tex]T_{2} = 500 * 0.4[/tex]
[tex]T_{2} = 200[/tex]
Hence, the second term is 200
