Answer:
Option C. 0.36 m/s² to the left.
Explanation:
The following data were obtained from the question:
Mass of skateboarder = 65.2 Kg
Force in the right direction (Fᵣ) = 31.8 N
Force in the left direction (Fₗ) = 55.2 N
Acceleration of the skateboarder =.?
Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:
Force in the right direction (Fᵣ) = 31.8 N
Force in the left direction (Fₗ) = 55.2 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 55.2 – 31.8
Fₙ = 23.4 N to the left
Thus, the net force acting on the skateboarder is 23.4 N to the left.
Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:
Mass of skateboarder = 65.2 Kg
Net force (Fₙ) = 23.4 N to the left
Acceleration (a) of the skateboarder =.?
Net force = mass × acceleration
23.4 N = 65.2 × a
Divide both side by 65.2
a = 23.4 / 65.2
a = 0.36 m/s² to the left.
Therefore, the acceleration of the skateboarder is 0.36 m/s² to the left.
