Question

What equation is graphed in this figure?


A. y−4=−13(x+2)

B. y−3=13(x+1)

C. y+2=−3(x−1)

D. y−5=3(x−1)

Answer 1

Answer:

c. $y + 2 = -3(x - 1)$

Step-by-step explanation:

By using a point on the line and the slope, we can determine the equation, in point-slope form, that is graphed in the figure.

Using two points, (1, -2) and (0, 1),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-2)}{0 - 1} = \frac{3}{-1} = -3$

m = -3

Using a point, (1, -2) and the slope (m), we can create an equation for the graph in point-slope form, by substituting x1 = 1, y1 = -2 and m = -3 in $y - y_1 = m(x - x_1)$.

Thus, we would have:

$y -(-2) = -3(x - 1)$

$y + 2 = -3(x - 1)$

The equation that is graphed in the figure is:

✔️$y + 2 = -3(x - 1)$