Given:
Equation of line is [tex]y=3x-7[/tex].
To find:
The equation of line which is parallel line to [tex]y=3x-7[/tex] and passes through (3,5) in function notation.
Solution:
Slope intercept form of a line is
[tex]y=mx+b[/tex]
where, m is slope and b is y-intercept.
On comparing the equation [tex]y=3x-7[/tex] with slope intercept form, we get
[tex]m=3[/tex]
So, slope of given line is 3.
Slope of parallel lines are same. Thus, the slope of parallel line is also 3.
Point slope form of a line is
[tex]y-y_1=m(x-x_1)[/tex]
where, m is slope.
The parallel line passes through (3,5) with slope 3. So, the equation of line is
[tex]y-5=3(x-3)[/tex]
[tex]y-5=3x-9[/tex]
Add 5 on both sides.
[tex]y=3x-9+5[/tex]
[tex]y=3x-4[/tex]
Function notation of this equation is
[tex]f(x)=3x-4[/tex]
Therefore, the equation equation in function notation is [tex]f(x)=3x-4[/tex].