Question

How many gallons of pure water should be evaporated from 160 gallons of a solution containing 12% salt

so that the remaining solution contains 20% salt?

What are you being asked to find in this problem?

O gallons of pure water

gallons of 12% salt solution

gallons of 20% salt solution

what is the original amount of solution in gallons? a=

Answer 1

Answer:

66 gallons

Step-by-step explanation:

Given that initially 160 gallons of a solution containing 12% salt.

So, the initial amount of salt = 12% of 160 = 12/100 x 160 = 19.2 gallons.

Let x gallons of water get evaporated so that the remaining solution contains 20% salt.

The remaining amount of solution = 160-x gallons.

As the initial amount of salt is still in the solution which is equal to 20% of the remaining solution, so

19.2 = 20% of (160-x)

$\Rightarrow 19.2 = \frac {20}{100}\times (160-x) \\\\\Rightarrow 19.2 = \frac {1}{5}\times (160-x) \\\\\Rightarrow 19.2 \times 5= 160-x \\\\\Rightarrow 96= 160-x \\\\\Rightarrow x= 160-96$

$\Rightarrow x= 66$ gallons

Hence, 66 gallons of water must be evaporated to get a 20% salt solution.

Answer 2

Answer:

its A, "gallons of pure water"

Step-by-step explanation: just did it on edg and got it right