Question

If angle A is congruent to itself by the Reflexive Property, which transformation could be used to prove ΔABC ~ ΔADE by AA similarity postulate? triangles ABC and ADE, in which point B is between points A and D and point C is between points A and E Translate triangle ABC so that point C lies on point D to confirm ∠C ≅ ∠D. Dilate ΔABC from point A by the ratio segment AD over segment AB to confirm segment AD ~ segment AB. Translate triangle ABC so that point B lies on point D to confirm ∠B ≅ ∠D. Dilate ΔABC from point A by the ratio segment AE over segment AC to confirm segment AE ~ segment AC.

Answer 1

Following are the solution to the given equation:

• If angle A is equal to itself due to Reflexive Property, move triangle ADE so that point D sits on point B to confirm $\angle D \cong \angle B$.
• This transformation can be used to demonstrate the assumption of $\Delta ABC \sim \Delta ADE$ via AA similarity.
• When an angle (A) is congruent to itself due to its reflexive quality, the transformation that may be used to show the $\Delta ABC \sim \Delta ADE$  by AA similarity postulate is:
• To validate $\angle D \cong \angle B$, translate triangle ADE so that point D is on point B.

Therefore, the final answer is " Triangle ADE are Translate since point D lies on point B to confirm $\angle D \cong \angle B$".

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