Question

A manufacturer of women’s blouses has noticed that 80% of their blouses have no flaws, 15% have one flaw, and 5% have two flaws. If you buy a new blouse from this manufacturer, the expected number of flaws will be:_________

a. 0.15
b. 0.20
c. 0.80
d. 1.00
e. none of the above

Answer 1

Answer:

b

Step-by-step explanation:

80% +15% +5%=100

15/100= 0.15

5/100= 0.05

therfore

0.15 + 0.05 = number of flaws

=0.20

Answer 2

Based on the flaws that the manufacturer notices, we can infer that the expected number of flaws will be 0.25 which is e. none of the above.

The expected number of flaws is a weighted average of the percentages that have flaws:

=∑ (Percentage of flaws x Number of flaws)

The expected number of flaws is therefore:

= (80% x 0) + (15% x 1) + (5% x 2)

= 15% + 10%

= 0.25

In conclusion, you would expected the number of flaws to be 0.25.

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