You count 60 onion cells in different stages of mitosis. Of those 60, 19 are in prophase, 14 in metaphase, 12 in anaphase, and 15 in telophase. If a full cycle is 24 hours (1440 minutes), which stage has the longest duration and how long is it in minutes?

a. Anaphase, 288 minutes
b. Prophase, 228 minutes
c. Prophase, 456 minutes
d. Anaphase. 567 minutes

According to this question, there are a total of 60 onion cells in different stages of mitosis. Of those 60, 19 are in prophase, 14 in metaphase, 12 in anaphase, and 15 in telophase. A full cell cycle lasts for 24 hours equivalent to 1440 minutes.

To calculate the amount of time spent in each stage of the mitotic process and discover which is the longest, we divide the number of cells in each state by the total number of cells and multiply by the total time in mins.

For prophase: 19/60 × 1440

= 456 minutes

For metaphase: 14/60 × 1440

= 336 minutes

For anaphase: 12/60 × 1440

= 288 minutes

For Telophase: 15/60 × 1440

= 360 minutes

Based on the calculation above, it can be realized that PROPHASE stage has the longest duration with a length of 456 minutes.

fichoh fichoh · Answer 2 · 2021-11-25T17:07:38+01:00

Using the ratio principle, the longest stage is Prophase with a duration of 456 minutes

The amount of time spent in each stage of Mitosis can be calculated thus :

(Number of onion per stage / total number of onions) × total time spent.
Total time spent = 24 hours = (60 × 24) = 1440 minutes

Time spent per stage :

Anaphase :

(12 / 60) × 1440 = 288 minutes

Prophase :

(19 / 60) × 1440 = 456 minutes

Metaphase :

(14 / 60) × 1440 = 336 minutes

Telophase :

(15 / 60) × 1440 = 360 minutes

Therefore, the stage with the longest duration is the Prophase stage and the duration is 456 minutes

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