Answer:
[tex]a_{n}[/tex] = 4n + 4
Step-by-step explanation:
There is a common difference d between consecutive terms in the sequence.
d = 12 - 8 = 16 - 12 = 20 - 16 = 4
This indicates the sequence is arithmetic with n th term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and d = 4 , then
[tex]a_{n}[/tex] = 8 + 4(n - 1) = 8 + 4n - 4 = 4n + 4
