Question

Find the momentum of a 23.1 g bullet fired at 621 m/s.
a. 1.43×104 Ns
b. 26.9Ns
c. 2.69×10–2Ns
d. 14.3Ns

Answer 1

Answer:

d. 14.3 Ns

Explanation:

Mass of the bullet (m) = 23.1 g = 0.0231 kg

Speed of the bullet (v) = 621 m/s

Momentum (p) is measured as the product of mass of the body and it's speed.

Mathematical Representation/Equation of Momentum:

$\boxed{ \bf{p = mv}}$

By using equation of momentum, we get:

$\rm \longrightarrow p = 0.0231 \times 621 \\ \\ \rm \longrightarrow p = 14.3 \: kg \: m {s}^{ - 1} \\ \\ \rm \longrightarrow p = 14.3 \: Ns$

Answer 2

The momentum of a 23.1g bullet fired at 621 m/s is 14.3Ns.

HOW TO CALCULATE MOMENTUM:

• Momentum is a product of an object's mass and velocity. That is, it can be calculated as follows:

• Momentum (p) = mass (m) × velocity (v)

• According to this question, a 23.1g bullet is fired at 621m/s. The momentum can be calculated thus:

• Mass of bullet in kg = 23.1/1000 = 0.00231kg

• Momentum (p) = 0.00231kg × 621m/s

• Momentum = 14.34Ns

• Therefore, the momentum of a 23.1g bullet fired at 621 m/s is 14.3Ns.

Learn more about momentum at: https://brainly.com/question/20301772?referrer=searchResults