Answer:
The energy of photon is 33.28×10⁻¹⁴ J
Explanation:
Given data:
Frequency of photon = 5.02×10²⁰ Hz
Energy of photon = ?
Solution:
E = h.f
h = planc'ks constant = 6.63×10⁻³⁴ Js
by putting values,
E = 6.63×10⁻³⁴ Js × 5.02×10²⁰ Hz
Hz = s⁻¹
E = 33.28×10⁻¹⁴ J
The energy of photon is 33.28×10⁻¹⁴ J.
