Answer:
1.9139 × 10²⁴ atoms Ca
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
127.38 g Ca
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Ca - 40.08 g/mol
Step 3: Convert
[tex]127.38 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca} )(\frac{6.022 \cdot 10^{23} atoms \ Ca}{1 \ mol \ Ca} )[/tex] = 1.91388 × 10²⁴ atoms Ca
Step 4: Check
We are given 5 sig figs. Follow sig fig rules and round.
1.91388 × 10²⁴ atoms Ca ≈ 1.9139 × 10²⁴ atoms Ca
