Question

A pile of pebbles has a weight of 95 kg.
Some of the pebbles put into a small bag.
The rest of the pebbles is put into a large bag.
The pebbles in the large bag weighs 45 kg more than the pebbles in the small
What is the weight of the pebbles in the large bag?​

Answer 1

Answer:

70kg

Step-by-step explanation:

s = small bag

b = big bag

Equations

s + b = 95

s + 45 = b

plug in

s + s + 45 = 95

2s + 45 = 95

2s = 50

s = 25

plug in to find big bag

25 + 45 = b

70 = b

Answer 2

Answer:

The weight of the pebbles in the large bag is 70kg.

Step-by-step explanation:

This looks like a substitution algebra problem. To do this, I’m going to mark the large bag with (L) and the small bag with the variable, (s). I will make first 2 equations to show the value. The first equation would be L=45+s. The second equation would be 95=L+s. Since L is literally 45+s, add this into the 2nd equation. This would be 95=45+s+s. You should have 95= 45+2s and you would subtract 45 from both sides then. Finally, divide 2s by 2 to get what the small bag weighs, (which is 25kg). To find the large bag’s weight, use the first equation to find the answer. L= 45+s or 25. The answer would bring us to 70 kg.