Answer correctly please !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!!

Answer:
[tex] m\angle EFG =43\degree[/tex]
Step-by-step explanation:
[tex] m\angle EFG +m\angle GFH = m\angle EFH\\\\
(3x-20)\degree + (3x+5)\degree =111\degree \\\\
(3x-20+3x +5)\degree =111\degree \\\\
(6x-15)\degree =111\degree \\\\
(6x-15) =111 \\\\
6x = 111 + 15\\\\
6x = 126\\\\
x = \frac{126}{6}\\\\
x = 21\\\\
m\angle EFG = (3x-20)\degree\\\\
m\angle EFG = (3\times 21-20)\degree\\\\
m\angle EFG = (63-20)\degree\\\\
m\angle EFG =43\degree\\[/tex]