Question

the length of a rectangle is 4 feet longer than its width.its area is 32 square feet.what are its dimensions?

Answer 1

Answer: Length=8, Width=4

Step-by-step explanation: I did this by trial and error, but you can also use an equation. The length is x+4, the width is x. Your equation would be x(x+4)=32. That is equal to x^2+4x=32. Solve this by completing the square. X^2+4x+ (4/2)^2=32+ (4/2)^2

X^2+4x+4=36. (X+2)(x+2)=36. X+2=6, x=4.