Question

Number 3.

In the diagram, AB is the tangent to the circle at P and PX is the diameter.

Given that BPQ = 42°, find PQX, PXQ and XPQ.

Answer 1

Answer:

see explanation

Step-by-step explanation:

∠ PQX = 90° ( angle in a semicircle )

∠ PXQ = 42° ( alternate angle theorem )

Angle between tangent and diameter is right, thus

∠ XPQ = 90° - 42° = 48°