Answer:
we get [tex]\mathbf{(g \ o \ f)(4)=9}[/tex]
Option C is correct.
Step-by-step explanation:
We are given:
[tex]f(x)=-x^3\\g(x)= |\frac{1}{8}x-1|[/tex]
We need to find (g о f)(4)
For finding (g о f)(4) we will first find g(f(x)) i.e putting value of f(x) inside g(x) and then put x=4
[tex](g \ o \ f)(x)=g(f(x))\\(g \ o \ f)(x)=|\frac{1}{8}(-x^3)-1 |[/tex]
Now, putting x=4
[tex](g \ o \ f)(x)=|\frac{1}{8}(-x^3)-1 |\\Put \ x=4\\(g \ o \ f)(4)=|\frac{1}{8}(-(4)^3)-1 |\\(g \ o \ f)(4)=|\frac{1}{8}(-64)-1 |\\(g \ o \ f)(4)=|-8-1 |\\(g \ o \ f)(4)=|-9| \\\\We \ will \ use \ absolute \ value \ i.e \ 9 \\(g \ o \ f)(4)=9[/tex]
So, we get [tex]\mathbf{(g \ o \ f)(4)=9}[/tex]
Option C is correct