A balloon filled with helium occupies 21.0ft³ at 55.0°F. Find the temperature of the helium if the volume of the balloon decreases to 11.0ft³. (Assume that the pressure is held constant.)​

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Answer:

Assuming pressure is held constant,the question reduces to a ratio and proportion type of question where;

At constant pressure,

21.0ft³-55.0°F

11.0fy³=11.0ft³/21.0ft³×55°F

The temperature is 28.809°F≈29°F

29°F is the temperature of the helium if the volume of the balloon decreases to 11.0ft³.

What is temperature?

Temperature expresses hotness and coldness or a measure of the average kinetic energy of the atoms or molecules in the system.

Assuming pressure is held constant, the question reduces to a ratio and proportion type of question where;

At constant pressure,

21.0ft³- 55.0°F

11.0fy³ = 11.0ft³ ÷ 21.0ft³ × 55°F

The temperature is 28.809°F ≈ 29°F

Hence, 29°F is the temperature of the helium if the volume of the balloon decreases to 11.0ft³.

Learn more about temperature here:

brainly.com/question/28004147

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